Question 1 — Linear functions (easy)
If $f(x) = 3x - 4$, what is the value of $f(5)$?
- $3$
- $11$
- $19$
- $1$
Answer: B. Substituting $x = 5$ gives $f(5) = 3(5) - 4 = 15 - 4 = 11$.
A linear function models a quantity that changes at a constant rate: $f(x) = mx + b$, where $m$ is the rate of change (slope) and $b$ is the starting value. The Digital SAT tests whether you can evaluate the function, build it from a description or two points, and — above all — interpret what $m$ and $b$ mean in a real context. Linear questions appear in every Math module, usually early, and they are points you cannot afford to leave behind.
Reading $f(x) = 12x + 30$ as “starts at 12, grows by 30.” The coefficient of $x$ is always the rate; the constant is always the starting value.
Computing $3(5) + 4 = 19$ for $f(x) = 3x - 4$. Distractors are built from exactly this sign slip — check the operation before you move on.
Writing $m = \dfrac{x_2 - x_1}{y_2 - y_1}$. Slope is rise over run — change in output over change in input.
Finding $x$ when the test asked for $f(x)$, or reporting the intermediate value. The last sentence of the stem decides what counts.
If $f(x) = 3x - 4$, what is the value of $f(5)$?
Answer: B. Substituting $x = 5$ gives $f(5) = 3(5) - 4 = 15 - 4 = 11$.
The full Linear Functions lesson inside Satisfied adds interpretation drills, table and graph variants, and a practice set that adapts to your level — with every mistake named in the review.
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